Potenzgesetze Theorie 13

Nein

$\huge \sqrt{x^{\frac13}}\quad = (x^{\frac13})^\frac12 = x^{(\frac13\cdot \frac12)}=x^{\frac16}$
$\quad$
$\quad\huge x^{\frac13^{\frac12}}=x^{\sqrt{\frac13}}=x^\frac1{\sqrt3} \qquad\rightarrow \qquad x^\frac1{\sqrt3} \neq x^\frac1{6}$